CHALLENGE YOUR GEOM STUDENTS OR YOUR MATH TEAM
In square ABCD of side 1, E is the point on diagonal AC such that AE=1.
(a) Explain without numerical calculation why
√2 < BE + DE < 2
(b) Show that BE+DE = 2(√(2-√2)) ≈ 1.531 without using Law of Cosines
(c) Be a math researcher! How might you generalize this?
Sent from my Verizon Wireless 4GLTE Phone
In square ABCD of side 1, E is the point on diagonal AC such that AE=1.
(a) Explain without numerical calculation why
√2 < BE + DE < 2
(b) Show that BE+DE = 2(√(2-√2)) ≈ 1.531 without using Law of Cosines
(c) Be a math researcher! How might you generalize this?
Sent from my Verizon Wireless 4GLTE Phone
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